Question
Download Solution PDF\(\rm \frac{6}{7}, 2\frac{3}{5}, \frac{3}{8}\ and \ 2\frac{8}{15}\) లో గరిష్ట మరియు కనిష్ట భిన్నాల మొత్తం:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFవివరణ -
ఇచ్చిన భిన్నాలు -
6/7 = 0.857
\(2\frac{3}{5} = \frac{13}{5}\) = 2.6
3/8 = 0.375
\( \ 2\frac{8}{15} = \frac{38}{15} = 2.533\)
స్పష్టంగా, కనిష్ట భిన్నం 3/8 మరియు గరిష్ట భిన్నం \(2\frac{3}{5} = \frac{13}{5}\)
మొత్తం = 3/8 + \(2\frac{3}{5} \)
= 3/8 + 13/5
= (15+ 104)/40
= 119/40 = \(2\frac{39}{40} \)
కాబట్టి ఎంపిక (2) సరైనది.
Last updated on Apr 30, 2025
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