The foci of an ellipse are (±3, 0) and its eccentricity is 1/3, find its equation.

Answer (Detailed Solution Below)

Option 1 :
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Detailed Solution

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Concept:

The general equation of the ellipse is:

Here, coordinates of foci are (±ae, 0).

Also, we have b2 = a2(1 - e2), where e is the eccentricity.

Calculation:

Since the coordinates of the foci are (±3, 0).

⇒ ae = 3

⇒ a × (1/3) = 3      (∵ e = 1/3)

⇒ a = 9

Now, b2 = a2(1 - e2)

⇒ b2 = 72

On putting the value of a2 and b2 in the general equation of an ellipse, we get

Hence, the equation of the ellipse is .

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