Question
Download Solution PDFThree perfect dice are rolled. Under the condition that no two show the same face, what is the probability that one of the faces shown is an ace (one)?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
⇒n(S) = 6 × 5 × 4
⇒ n(E) = n (one of the faces shown is an ace.)
= 3(1 × 5 × 4) = 3 × 5 × 4
⇒ \(P(E) = \frac{3\times 5\times 4}{6\times 5\times4} = \frac{1}{2}\)
∴ Option (d) is correct
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