Question
Download Solution PDFA box contains 2 black, 4 yellow and 6 white balls. Three balls are drawn in succession with replacement. What is the probability that all three are of the same colour?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Black = 2, yellow = 4 and white = 6
⇒ Total Balls = = 2 + 4 + 6 = 12
P (all three are of the same colour).
= \(\frac{2^3}{12^3}+ \frac{4^3}{12^3} +\frac{6^3}{12^3} = \frac{1}{6}\)
∴ Option (a) is correct
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