A box contains 2 black, 4 yellow and 6 white balls. Three balls are drawn in succession with replacement. What is the probability that all three are of the same colour?

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NDA-II 2024 (Maths) Official Paper (Held On: 01 Sept, 2024)
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  1. 1/6
  2. 1/36
  3. 1/12
  4. 5/12

Answer (Detailed Solution Below)

Option 1 : 1/6
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Detailed Solution

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Explanation:

Black = 2, yellow = 4 and white = 6

⇒ Total Balls = = 2 + 4 + 6 = 12

P (all three are of the same colour).

\(\frac{2^3}{12^3}+ \frac{4^3}{12^3} +\frac{6^3}{12^3} = \frac{1}{6}\)

∴ Option (a) is correct

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