Question
Download Solution PDFThe head loss due to friction in a pipe of 1 m diameter and 1.5 km long when water is flowing with a velocity of 1 m/s is (Darcy's friction factor fD= 0.02 and acceleration due to gravity g =10m/s2)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Head loss due to friction is given by:
\({\rm{h\;}} = {\rm{\;}}\frac{{{\rm{f}}L{{\rm{v}}^2}}}{{2{\rm{gd}}}}\)
d = diameter of pipe, f = friction factor, L = length of pipe, and v = velocity of flow
Calculation:
Given:
d = 1 m, L = 1.5 km = 1500 m, v = 1 m/s, f = 0.02, g = 10 m/s2
Head loss due to friction is
\({\rm{h\;}} = {\rm{\;}}\frac{{{\rm{f}}L{{\rm{v}}^2}}}{{2{\rm{gd}}}}\)
\({\rm{h\;}} = {\rm{\;}}\frac{{{\rm{0.02}}\times 1500 \times{{\rm{1}}^2}}}{{2{\rm{\times10\times1}}}}\)
h = 1.5 m
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