The head loss due to friction in a pipe of 1 m diameter and 1.5 km long when water is flowing with a velocity of 1 m/s is (Darcy's friction factor fD= 0.02 and acceleration due to gravity g =10m/s2)

This question was previously asked in
ISRO VSSC Technical Assistant Mechanical 9 June 2019 Official Paper
View all ISRO Technical Assistant Papers >
  1. 1.5 m
  2. 0.5 m
  3. 1 m
  4. 2 m

Answer (Detailed Solution Below)

Option 1 : 1.5 m
Free
ISRO Technical Assistant Mechanical Full Mock Test
2.7 K Users
80 Questions 80 Marks 90 Mins

Detailed Solution

Download Solution PDF

Concept:

Head loss due to friction is given by:

\({\rm{h\;}} = {\rm{\;}}\frac{{{\rm{f}}L{{\rm{v}}^2}}}{{2{\rm{gd}}}}\)

d = diameter of pipe, f = friction factor, L = length of pipe, and v = velocity of flow

Calculation:

Given:

d = 1 m, L = 1.5 km = 1500 m, v = 1 m/s, f = 0.02, g = 10 m/s2

Head loss due to friction is

\({\rm{h\;}} = {\rm{\;}}\frac{{{\rm{f}}L{{\rm{v}}^2}}}{{2{\rm{gd}}}}\)

\({\rm{h\;}} = {\rm{\;}}\frac{{{\rm{0.02}}\times 1500 \times{{\rm{1}}^2}}}{{2{\rm{\times10\times1}}}}\)

h = 1.5 m

Latest ISRO Technical Assistant Updates

Last updated on May 30, 2025

-> The ISRO Technical Assistant recruitment 2025 notification has been released at the official website. 

-> Candidates can apply for ISRO recruitment 2025 for Technical Assistant from June 4 to 18.

-> A total of 83 vacancies have been announced for the post of Technical Assistant.

-> The Selection process consists of a written test and a Skill test.

-> Candidates can also practice through ISRO Technical Assistant Electrical Test Series, ISRO Technical Assistant Electronics Test Series, and ISRO Technical Assistant Mechanical Test Series to improve their preparation and increase the chance of selection. 

More Friction Loss (Darcy Weisbach Equation) Questions

Get Free Access Now
Hot Links: teen patti star login teen patti download teen patti master purana teen patti bindaas teen patti refer earn