Question
Download Solution PDFThe maximum power dissipation capacity of a transistor is 50 mW. If the collector emitter voltage is 10 V. What is the safe collector current that can be allowed through the transistor?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The power capacity of a transistor is given by:
Pdiss. = VCE × IC
VCE = Collector emitter voltage
IC = Collector current
Application:
Given Pdiss(max) = 50 mW
VCE = 10 V
Pdiss(max) = VCE(max)× IC(max)
\(I_C(max)=\frac{50~mW}{10~V}=5~mA\)
To prevent the transistor from destroying or from excessive heating, the safe collector current would be 2.5 mA, which is less than the maximum allowed collector current of 5 mA.
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