The maximum power dissipation capacity of a transistor is 50 mW. If the collector emitter voltage is 10 V. What is the safe collector current that can be allowed through the transistor?

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VSSC ISRO Technical Assistant Electronics 8 Feb 2015 Official Paper
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  1. 5 mA
  2. 2.5 mA
  3. 10 mA
  4. 25 mA

Answer (Detailed Solution Below)

Option 2 : 2.5 mA
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Detailed Solution

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Concept:

The power capacity of a transistor is given by:

Pdiss. = VCE × IC

VCE = Collector emitter voltage

IC = Collector current

Application:

Given Pdiss(max) = 50 mW

VCE = 10 V

Pdiss(max) = VCE(max)× IC(max)

\(I_C(max)=\frac{50~mW}{10~V}=5~mA\)

To prevent the transistor from destroying or from excessive heating, the safe collector current would be 2.5 mA, which is less than the maximum allowed collector current of 5 mA.

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