Question
Download Solution PDFThe ratio of the moment of inertia of the two objects A and B is 1 : 2. If the ratio of the angular velocity of the object A to object B is 2 : 1, then find the ratio of the angular momentum of the object A to object B.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
Angular momentum:
- Angular momentum is the property of any rotating object given by moment of inertia times angular velocity.
- It is a vector quantity.
- Its SI unit is kg-m2/sec.
- If I and ω are the moment of inertia and the angular velocity respectively, then the angular momentum is given as,
⇒ L = Iω
⇒ L = rP
Where r = radius of rotation and P = linear momentum
CALCULATION:
Given \(\frac{I_A}{I_B}=\frac{1}{2}\), and \(\frac{\omega_A}{\omega_B}=\frac{2}{1}\)
- Angular momentum is the property of any rotating object given by moment of inertia times angular velocity.
- If I and ω are the moment of inertia and the angular velocity respectively, then the angular momentum is given as,
⇒ L = Iω -----(1)
- By equation 1 the angular momentum of the object A is given as,
⇒ LA = IAωA -----(2)
- By equation 1 the angular momentum of the object B is given as,
⇒ LB = IBωB -----(3)
By equation 2 and equation 3,
\(\Rightarrow \frac{L_A}{L_B}=\frac{I_A\omega_A}{I_B\omega_B}\)
\(\Rightarrow \frac{L_A}{L_B}=\frac{1}{2}\times\frac{2}{1}\)
\(\Rightarrow \frac{L_A}{L_B}=\frac{1}{1}\)
- Hence, option 1 is correct.
Last updated on Jun 26, 2025
-> The Indian Coast Guard Navik GD Application Deadline has been extended. The last date to apply online is 29th June 2025.
-> A total of 260 vacancies have been released through the Coast Guard Enrolled Personnel Test (CGEPT) for the 01/2026 and 02/2026 batch.
-> Candidates can apply online from 11th to 25th June 2025.
-> Candidates who have completed their 10+2 with Maths and Physics are eligible for this post.
-> Candidates must go through the Indian Coast Guard Navik GD previous year papers.