Twelve percent of bananas bought by a fruit vendor got lost during transportation. On selling the remaining bananas, the vendor's overall profit turned out to be 4%. If the vendor had not lost any bananas and had sold them at the price of the remaining bananas, what would have been his profit percentage ? 

Formula used:

Profit % = [(SP - CP)/CP] × 100

Calculation:

The vendor initially bought 100 bananas at a cost of 1 Rs each, so the total cost is 100 Rs.

12% i.e. 12 bananas lost during transportation.

Remaing bananas are 100 - 12 = 88.

Since the remaining bananas are sold at a 4 % profit

Selling Price of  88 bananas = 100 (1 + 4/100) = 104

Selling Price of 1 banana = 104/88 = 13/11

Selling Price of 100 bananas = 100 × (13/11) = 118.18

As the cost price of 100 bananas was 100 Rs.

Profit % = [(118.18 - 100)/100] × 100

∴ Profit % = 18.18% or \(18 \frac{2}{11} \%\)