Question
Download Solution PDFWhat is the minimum value of the function f(x) = log10(x2 + 2x + 11)?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
f(x) = log10 (x2 + 2x + 11) for minimum f'(x) = 0
⇒ \(\frac{2x + 2 }{x^2+2x+11} = 0\) .. (Since x2 +2x + 11 > 0)
At x = –1, we get minumum value of f(x).
⇒ f(–1) = log1010 = 1
Last updated on May 30, 2025
->UPSC has released UPSC NDA 2 Notification on 28th May 2025 announcing the NDA 2 vacancies.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced for cycle 2. The written examination will be held on 14th September 2025.
-> Earlier, the UPSC NDA 1 Exam Result has been released on the official website.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.