What will be the tensile force required to cause an elongation of 0.045 mm in a steel rod of 1000 mm length and 12 mm diameter, (where E = 2 × 106 kg/cm2)?

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OSSC JE Civil Mains Official Paper: (Held On: 16th July 2023)
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  1. 166 kg
  2. 102 kg
  3. 204 kg
  4. 74 kg

Answer (Detailed Solution Below)

Option 2 : 102 kg
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Detailed Solution

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Elongation of rod is given by:

P = 3000 kg

E = 2 × 106 kg/cm2

D = diameter = 12 mm = 1.2 cm

A = Area = 

L = length = 1 m = 1000 mm

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