Question
Download Solution PDFIf the external diameter of a hollow shaft is three times greater than its internal diameter, what is the ratio of its torque-carrying capacity compared to that of a solid shaft of identical material and the same outer diameter?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The torque capacity of a shaft is proportional to its polar moment of inertia:
\( T \propto \frac{\pi}{16}(D^4 - d^4) \)
Given:
- Solid shaft: \(T_s = \frac{\pi}{16}D^4\)
- Hollow shaft: d = D/3
Hollow Shaft Torque:
\( T_h = \frac{\pi}{16}(D^4 - (D/3)^4) = \frac{\pi}{16}D^4(1 - 1/81) = \frac{\pi}{16}D^4 \times \frac{80}{81} \)
⇒ \( \frac{T_h}{T_s} = \frac{80}{81} \)
Last updated on Jun 7, 2025
-> RRB JE CBT 2 answer key 2025 for June 4 exam has been released at the official website.
-> Check Your Marks via RRB JE CBT 2 Rank Calculator 2025
-> RRB JE CBT 2 admit card 2025 has been released.
-> RRB JE CBT 2 city intimation slip 2025 for June 4 exam has been released at the official website.
-> RRB JE CBT 2 Cancelled Shift Exam 2025 will be conducted on June 4, 2025 in offline mode.
-> RRB JE CBT 2 Exam Analysis 2025 is Out, Candidates analysis their exam according to Shift 1 and 2 Questions and Answers.
-> The RRB JE Notification 2024 was released for 7951 vacancies for various posts of Junior Engineer, Depot Material Superintendent, Chemical & Metallurgical Assistant, Chemical Supervisor (Research) and Metallurgical Supervisor (Research).
-> The selection process includes CBT 1, CBT 2, and Document Verification & Medical Test.
-> The candidates who will be selected will get an approximate salary range between Rs. 13,500 to Rs. 38,425.
-> Attempt RRB JE Free Current Affairs Mock Test here
-> Enhance your preparation with the RRB JE Previous Year Papers.