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When the EMF of two cells is compared in a potentiometer experiment, the ratio of balancing length is obtained as 2 ∶ 5. If one of the cells has an EMF of 1.2 V, the other cell's EMF is ______.

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  1. 4.5 V (or) 6.0 V 
  2. 0.3 V (or) 2.4 V
  3. 3.0 V (or) 6.0 V
  4. 0.48 V (or) 3.0 V

Answer (Detailed Solution Below)

Option 4 : 0.48 V (or) 3.0 V
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Detailed Solution

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Given:

 and 

Concept: 

The basic principle of of the Potentiometer is that the potential drop(or EMF) across any section of the wire will be directly proportional to the length of the wire, provided the wire is of a uniform cross-sectional area and a uniform current flows through the wire.

 

Explanation:

So, for two cells  

Case-I-When EMF , 

 

Case-II-When EMF 

 

So, the correct answer is 

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Q1.The current in the primary circuit of a potentiometer wire is 0.5 A, ρ for the wire is 4 × 10-7 Ω-m and area of cross- section of wire is 8 × 10-6 m2. The potential gradient in the wire would be
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Q10.A potentiometer wire is supplied a constant voltage of 3 V. A cell of emf 1.08 V is balanced by the voltage drop across 216 cm of the wire. The total length of the potentiometer wire is - 

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