Question
Download Solution PDFA potentiometer wire is supplied a constant voltage of 3 V. A cell of emf 1.08 V is balanced by the voltage drop across 216 cm of the wire. The total length of the potentiometer wire is -
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFormula Used:
\(\frac{E_1}{E_2}=\frac{l_1}{l_2}\)
Application:
We have,
E1 = 3 V (Supply voltage or cell terminal voltage)
E2 = 1.08 V (voltage drop across the wire for balancing)
l2 = 216 cm (length of wire were at which voltage drop occurs)
l1 = total length of wire
From the above formula,
l1 = \(l_2\times \frac{E_1}{E_2}=216\times \frac{3}{1.08}=600\ cm\)
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