A body 1 in the form of a sphere of 2 cm radius at temperature T1 is located in body 2, which is a hollow cube of 5 cm side and is at temperature T2 (T2 < T1). The shape factor F21 for radiation heat transfer becomes:

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  1. 0.34
  2. 0.43
  3. 0.57
  4. 0.63

Answer (Detailed Solution Below)

Option 1 : 0.34
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Concept:

Shape Factor is defined as the fraction of radiation energy leaving a surface that reaches another surface, for example, F12 means the fraction of energy leaving the surface 1 reaches surface 2.

.Summation Rule: F11 + F12 = 1

Reciprocity theorem: AF12 = AF21 (A is the surface area)

Calculation:

Let 1 denote the sphere and 2 denote the cube

2 M.J Madhu 17.04.20 D 1

Given, radius of the sphere = 2 cm, side of the cube = 5 cm

For sphere F11 = 0, F12 = 1 (All radiations from sphere fall on the cube)

A1 = 4πr2

A2 = 6a2

Reciprocity theorem

A1 F12 = A2 F21   

\({F_{21}} = \frac{{{A_1}}}{{{A_2}}} = \;\frac{{4\pi {2^2}}}{{6\; \times \;{5^2}}} = 0.335\;\;\)

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