A pitot-static tube is used to measure the velocity of water in a pipe. The stagnation pressure head is 6 m and static pressure head is 5 m. What is the velocity of flow assuming the coefficient of tube equal to 0⋅98? (Take acceleration due to gravity as 9⋅81 m/s²)

Concept:

A Pitot Tube is a flow measurement appliance used to calculate the fluid flow velocity.

The Velocity of Flow by Pitot Tube is given by

\(V = C_v\sqrt{2gh}\)

where C_v = Coefficient of Tube, g = Acceleration due to Gravity, h = Pressure Head

Pressure Head (h) is given by

h = h_s - h_t

where hs = Stagnation Pressure Head, ht = Static Pressure Head

Calculation:

Given:

g = 9.81 m/s², C_v = 0.98, h_s = 6 m, h_t = 5 m

Pressure Head, h = 6 - 5 = 1m

Velocity, \(V = 0.98\sqrt{2× 9.81× 1}\)

V = 0.98 × 4.429

Velocity of Flow, V = 4.34 m/s