Consider two coaxial cylinders of same length L, with vacuum inside them. The radii of the inner solenoid and the outer solenoid are r1 and r2 (> r1), respectively. The number of turns per unit length are n1 and n2 for the inner solenoid and the outer solenoid, respectively. The mutual inductance is:

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  1. π μ0  n1 n2 \(\rm r_2^2\) L
  2. π μ0 n1 n2 \(\rm r_1^2\) L
  3. 4π μ0  n1 n2 \(\rm r_1^2\) L
  4. 4π μ0  n1 n2 \(\rm r_2^2\) L

Answer (Detailed Solution Below)

Option 2 : π μ0 n1 n2 \(\rm r_1^2\) L
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Detailed Solution

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Concept:

  • Mutual Inductance: 
    • ​​When two coils are brought in proximity to each other the magnetic field in one of the coils tends to link with the other.

  • This further leads to the generation of voltage in the second coil.
  • This property of a coil that affects or changes the current and voltage in a secondary coil is called mutual inductance
  • The mutual inductance, M = π μ0  n1 n2 \(\rm r_1^2\) L.

Explanation:

Let's consider L is the length of the coaxial cylinder.

n1 and n2 are the numbers of turns of the inner solenoid and the outer solenoid respectively.

The mutual inductance is π μ0 n1 n2 \(\rm r_1^2\) L.

Additional Information

  •  Self-inductance:
    • Self-inductance is the property of the current-carrying coil that resists or opposes the change of current flowing through it.
    • This occurs mainly due to the self-induced emf produced in the coil itself.

F1 Madhuri Defence 20.12.2022 D9

  • The self inductance, L = μr μ0 n2 A L
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