Consider a parallel-plate capacitor, each of the plates has an area S and they are separated by a distance d. Assume that plates 1 and 2 carry charges +Q and -Q uniformly distributed on them. The energy stored in the capacitor is

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UPSC ESE (Prelims) Electronics and Telecommunication Engineering 19 Feb 2023 Official Paper
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  1. \(-\frac{Q}{\varepsilon S} a_x\)
  2. \(\frac{Q d}{\varepsilon S}\)
  3. \(\frac{1}{2 C} Q^2\)
  4. \(\frac{1}{2} Q \cdot C\)

Answer (Detailed Solution Below)

Option 3 : \(\frac{1}{2 C} Q^2\)
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Parallel plate capacitor: A parallel plate capacitor is a type of capacitor that consist of two parallel and closely spaced conductive plates seperated by a dielectric material.

Energy stored in capacitor = \(\frac{1}{2}CV^2 \)

Where, Q is the charge on the capacitor.

V is voltage.

C is capacitance.

\(\frac{1}{2}C(\frac{Q}{C})^2\)

=\(\frac{1}{2C}Q^2\)

Here, option 3 is correct.

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