Question
Download Solution PDFDeepak walks 1 km towards east, then he turns to south and walks 5 km. Again he turns to east and walks 2 km. After this he turns to north and walks 9 km. Now, how far is he from his starting point ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Deepak walks 1 km towards east, then he turns to south and walks 5 km.
Again he turns to east and walks 2 km. After this he turns to north and walks 9 km.
BY applying Pythagoras Theorem:
(AB)2 = (AC)2 + (CB)2
(AB)2 = (3)2 + (4)2
(AB)2 = 9 + 16
AB = √25
AB = 5 km
Thus, Deepak is 5 km far from the starting position.
Hence, "Option 4" is the correct answer.
Last updated on Feb 11, 2025
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