Find the nearest approximate weight of the part shown in the figure. ρ = 10 gm/cm3 (π = 22/7)

Note: All dimensions are in mm

F2 Engineering Savita 5-4-23 D1

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  1. 1500 gm
  2. 1560 gm
  3. 1250 gm
  4. 1435 gm

Answer (Detailed Solution Below)

Option 4 : 1435 gm
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Detailed Solution

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Concept:

Density:

  • The density of a material shows the denseness of that material in a specific given area.
  • A material’s density is defined as its mass per unit volume.
  • Density is essentially a measurement of how tightly matter is packed together.
  • Though the SI unit of density is kg/m³, for convenience we use gm/cm³ for solids, g/ml for liquids, and g/L for gases.

Density = \(\frac{Mass}{Volume}\)

Calculation:

Given:

Total volume (V) = (Volume of cuboid) - (Volume of cylinder)

⇒ V = (100 × 50 × 30) - (\(\frac{\pi}{4}\) × 282 × 10) 

⇒ V = 150000 - 6157.52 = 143842.47 mm3

⇒ V = 143842.47 × 10-3 cm3 = 143.84 cm3

∵ Density = \(\frac{Mass}{Volume}\)

⇒ \(10=\frac{Mass}{143.84}\)

⇒ Mass = 1438.4 grams

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