Question
Download Solution PDFFor a single degree of freedom viscous damped system, if the frequency ratio is greater than √2, it implies that:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Machine transmissibility,
\(\epsilon = \frac{F_t}{F_o} \)
\(\Rightarrow \epsilon = \frac{{\sqrt {1 + {{\left( {\frac{{2\zeta \omega }}{{{\omega _n}}}} \right)}^2}} }}{{\sqrt {{{\left( {1 - {{\left( {\frac{\omega }{{{\omega _n}}}} \right)}^2}} \right)}^2} + {{\left( {\frac{{2\zeta \omega }}{{{\omega _n}}}} \right)}^2}} }}\)
Machine transmissibility depends upon 'ω /ωn'→ (within the machine) = q (say)
ζ = Damping factor
Damping is beneficial up to a ratio of
\(\frac{\omega }{{{\omega _n}}}\left\langle {\sqrt 2 , \epsilon\;\;will \uparrow ,\;} \epsilon \right\rangle 1,\; \epsilon = machine\;transmissability\)
Whereas no need for damping, less damping, If the ratio of
\(\frac{\omega }{{{\omega _n}}} > \sqrt 2 ,\;\epsilon \;will \downarrow ,\;\epsilon < 1\)
Explanation:
- For all the value of the damping ratio, the transmissibility is less than one when the ratio of natural and forced frequency is greater than root 2 or \(\frac{\omega }{{{\omega _n}}} > \sqrt 2\)
⇒ \(\epsilon = \frac{F_t}{F_o} <1\)
- For all the value of damping ratio, the transmissibility is greater than one when the ratio of natural and forced frequency is less than root 2 and here the chances of getting infinite frequency is also there when the ratio will be 1, so we have to provide damping here only.
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