\(\rm \int \frac{dx}{x^{2}+4}\) का मूल्यांकन करें।

  1. \(\rm \frac{1}{4}tan^{-1}\frac{x}{4}+C\)
  2. \(\rm \frac{1}{2}tan^{-1}\frac{x}{2}+C\)
  3. \(\rm tan^{-1}\frac{x}{4}+C\)
  4. \(\rm tan^{-1}\frac{x}{2}+C\)

Answer (Detailed Solution Below)

Option 2 : \(\rm \frac{1}{2}tan^{-1}\frac{x}{2}+C\)
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Detailed Solution

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अवधारणा:

  • \(\rm \int \frac{dx}{x^{2}+a^{2}}=\frac{1}{a}tan^{-1}\frac{x}{a}+C\)


गणना:

दिया गया: \(\rm \int \frac{dx}{x^{2}+4}\)

इस सूत्र का उपयोग करते हुए, \(\rm \int \frac{dx}{x^{2}+a^{2}}=\frac{1}{a}tan^{-1}\frac{x}{a}+C\)

\(\rm \Rightarrow\int \frac{dx}{x^{2}+4}=\int \frac{dx}{x^{2}+2^{2}}= \frac{1}{2}tan^{-1}\frac{x}{2}+C\)

इसलिए, सही उत्तर विकल्प 2 है

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