रेखाओं y = 2x + 3 और y = 2x + 4 के बीच की दूरी ____ है। 

  1. 1
  2. \(\rm \frac{1}{\sqrt{5}}\)
  3. \(\rm \frac{7}{\sqrt{5}}\)
  4. \(\rm \frac{-7}{\sqrt{5}}\)

Answer (Detailed Solution Below)

Option 2 : \(\rm \frac{1}{\sqrt{5}}\)
Free
CRPF Head Constable & ASI Steno (Final Revision): Mini Mock Test
20.7 K Users
40 Questions 40 Marks 45 Mins

Detailed Solution

Download Solution PDF

अवधारणा:

दो समानांतर रेखाओं के बीच की दूरी:

दो समानांतर रेखाओं y = mx + c1 और y = mx + c2 के बीच की दूरी d = \(\rm \frac{\left | c_{2} - c_{1} \right |}{\sqrt{1 + m^{2}}}\) द्वारा दी जाती है

गणना:

दी गई रेखाओं के समीकरण y = 2x + 3 और y = 2x + 4 हैं

लंबवत दूरी = \(\rm \frac{\left | 4- 3\right |}{\sqrt{1 + 2^{2}}}\) = \(\rm \frac{1}{\sqrt{5}}\)

रेखाओं y = 2x + 3 और y = 2x + 4 के बीच की दूरी \(\rm \frac{1}{\sqrt{5}}\) है

Latest Indian Coast Guard Navik GD Updates

Last updated on Jun 11, 2025

-> The Indian Coast Guard Navik GD is a prestigious exam for those who want to serve the country in Defence Services.

-> A total of 260 vacancies have been released through the Coast Guard Enrolled Personnel Test (CGEPT) for the 01/2026 and 02/2026 batch.

-> Candidates can apply online from 11th to 25th June 2025.

-> Candidates who have completed their 10+2 with Maths and Physics are eligible for this post. 

-> Candidates must go through the Indian Coast Guard Navik GD previous year papers.

More Distance Formula Questions

More Lines Questions

Get Free Access Now
Hot Links: teen patti casino teen patti jodi teen patti gold apk