एक रेडियोधर्मी पदार्थ की अर्धायु 10 वर्ष है और इसका प्रारंभिक द्रव्यमान 1 g है। 20 वर्षों के बाद शेष मात्रा ________ है।

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  1. 0.75 g
  2. 1.00 g
  3. 0.50 g
  4. 0.25 g

Answer (Detailed Solution Below)

Option 4 : 0.25 g
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दिया गया​ है:

अर्धायु \(t_{1/2}\)=10 वर्ष 

प्रारम्भिक द्रव्यमान \(N_o\)=1g

समय T=20 वर्ष 

संकल्पना:

अर्धायु: अर्धायु वह समय अवधि है जिसके बाद रेडियोधर्मी तत्व की आधी मात्रा क्षय हो जाती है।

n अर्धायु के बाद पदार्थ का अंश इस प्रकार दिया जाता है,

  • \(N=\frac{N_o}{2^n}\)

जहां \(N_o\) प्रारंभिक द्रव्यमान है। 

\(n=\frac{\text{Total time}}{\text{Half life}}=\frac{T}{t_{1/2}}\)

स्पष्टीकरण​:

दिए गए सभी मानों को उपरोक्त सूत्र में रखें, हमें निम्न मिलता है,

\(n=\frac{T}{t_{1/2}}=\frac{20}{10}=2\ years\)

\(N=\frac{N_o}{2^n}=\frac{1}{2^2}\)

\(N=\frac{1}{4}=0.25g\)

अतः, सही उत्तर विकल्प-4-0.25 g है।

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