Question
Download Solution PDF\(\rm 2\sin \left(A-\dfrac{\pi}{3}\right)\) का न्यूनतम मान क्या है जहां A ∈ R?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
sine फलन की सीमा [-1,1] है अर्थात \(\rm \Rightarrow -1\leq sin(x) \leq 1\)
गणना:
हम लिख सकते हैं, \(\rm sin(A - \frac{\pi}{3}) \in [-1,1]\)
\(\rm \Rightarrow -1\leq sin(A - \frac{\pi}{3}) \leq 1\)
\(\rm \Rightarrow -2\leq 2sin(A - \frac{\pi}{3}) \leq 2\)
इसलिए संबंध से हम यह निष्कर्ष निकाल सकते हैं कि 2sin (A - \(\rm \frac{\pi}{3}\)) का न्यूनतम मान -2 है।
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