Question
Download Solution PDFIn a potentiometer circuit, a cell of 1.5 V EMF gives balance point at 30 cm length of wire. If another cell of 2.5 V EMF replaces the first cell, then at what length of the wire will the balance point occur?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is option 1):(50 cm)
Concept:
As we know in a potentiometer EMF has two cells in which ℓ1 and ℓ2 be the null points and E1 and E2 be the EMFs, therefore we can write it as,
\(\frac{{{E_1}}}{{{E_2}}} = \frac{{{\ell_1}}}{{{\ell_2}}}\)
Calculation:
Given:
E1 = 1.5 V
E2 = 2.5 V
l1 = 30 cm
l2 = ?
Using\(\frac{{{E_1}}}{{{E_2}}} = \frac{{{\ell_1}}}{{{\ell_2}}}\)
we get;
l2 = l1 × \(E_2 \over E_1\)
= 30 × \(2.5 \over 1.5\)
= 50 cm
Last updated on Jun 2, 2025
-> HPCL Engineer 2025 notification has been released on June 1, 2025.
-> A total of 175 vacancies have been announced for the HPCL Engineer post in Civil, Electrical, Mechanical, Chemical engineering.
-> HPCL Engineer Online application will be activated from 1st June 2025 to 30th June 2025.
-> Candidates with a full-time engineering discipline in the relevant stream are eligible to apply.
-> The selection will be based on a Computer Based Test Group Task and/or Interview. Prepare for the exam using HPCL Engineer Previous Year Papers.