Question
Download Solution PDFOABC is a rhombus whose three vertices lie on a circle with centre at O. If the area of the rhombus is 32√3 square cm, then what is the radius of the circle ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFormula used:
Area of equilateral triangle = (√3/4) (side)2
Calculation:
OA = OB = OC = radius (r)
Since OABC is a rhombus
BC = AB = r
Therefore, ΔOAB & ΔOBC are equilateral trainge
According to the question
Area of rhombus = 32√3
Area of ΔOAB + Area of ΔOBC = 32√3
(√3/4)r2 + (√3/4)r2 = 32√3
2 [(√3/4) × r2] = 32√3
r2 = 64
r = 8 cm
∴ The radius of the circle is 8 cm2
Last updated on Jun 18, 2025
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