Question
Download Solution PDFPipe A can fill a tank in 828 minutes and Pipe B can empty the same tank in 1035 minutes. If both pipes are opened together, how many hours will it take to fill the empty tank?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Pipe A can fill the tank in 828 minutes
Pipe B can empty the tank in 1035 minutes
Formula used:
Total work = LCM of 828 and 1035
Efficiency = Work ÷ Time
Net efficiency = A's efficiency - B's efficiency
Time taken = Total work ÷ Net efficiency
Calculations:
LCM of 828 and 1035 = 4140 units (total work)
A's efficiency = 4140 ÷ 828 = 5 units/min
B's efficiency = 4140 ÷ 1035 = 4 units/min
Net efficiency = 5 - 4 = 1 units/min
Time = 4140 ÷ 1 = 4140 minutes
Convert to hours = 4140 ÷ 60 = 69 hours
∴ Time to fill the tank = 69 hours
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