Question
Download Solution PDFThe effective width of the simply supported flanged beam with Df = 100 mm, l0 = 12000 mm, bw = 350 mm having d = 500 mm, Fe 415 steel grade and M 20 grade is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
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Effective Width of Flange |
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Monolithic Beams |
T – Beams |
\({b_f} = {b_w} + \frac{{{l_o}}}{6} + 6{d_f}\) |
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L – Beams |
\({b_f} = {b_w} + \left( {\frac{{{l_o}}}{12} + 3{d_f}} \right)\) |
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Isolated Beams |
T – Beams |
\({b_f} = {b_w} + \frac{{{l_o}}}{{\frac{{{l_o}}}{b} + 4}}\) |
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L – Beams |
\({b_f} = {b_w} + \frac{{0.5 \times {l_o}}}{{\frac{{{l_o}}}{b} + 4}}\) |
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Where
bf = effective width of flange
lo = distance between points of zero moments in the beam
bw = breadth of the web
df = thickness of the flange, and
b = actual width of the flange
\({b_f} = {b_w} + \frac{{{l_o}}}{6} + 6{d_f}\)
l0 = 12000 mm, df = 100 mm, bw = 350 mm
\({b_f} = {350} + \frac{{{12000}}}{6} + 6\times{100}\)
bf = 2950 mm
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