Question
Download Solution PDFThe equation of straight line passing through the point (1, 2) and parallel to the line y = 3x + 1 is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Equation of a line parallel to a given line ax + by + c = 0 is
ax + by + λ = 0,
where λ is a constant
Calculation:
We have,y = 3x + 1
⇒ 3x - y + 1 = 0
Equation of a line parallel to above line is
3x - y + λ = 0 -----(1)
It is passing through point (1, 2)
⇒ (3 × 1) - 2 + λ = 0
⇒ 1 + λ = 0
⇒ λ = -1
Put this value in equation (1)
⇒ 3x - y - 1 = 0
⇒y - 2 = 3x - 1 - 2
⇒ y - 2 = 3x - 3
⇒y - 2 = 3(x - 1)
Last updated on May 19, 2025
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