The distance of point (2, 3) from the origin is.

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Bihar STET TGT (Maths) Official Paper-I (Held On: 04 Sept, 2023 Shift 2)
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  1. \(\sqrt{10}\)
  2. \(\sqrt{12}\)
  3. \(\sqrt{13}\)
  4. \(\sqrt{11}\)

Answer (Detailed Solution Below)

Option 3 : \(\sqrt{13}\)
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Detailed Solution

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Concept -

The distance between a point (x, y) and the origin (0, 0) in a 2D plane is given by the distance formula:

\( \text{Distance} = \sqrt{x^2 + y^2}\)

Explanation -

For the point (2, 3), the distance from the origin is:

\( \text{Distance} = \sqrt{2^2 + 3^2} \\ \text{Distance} = \sqrt{4 + 9} \\ \text{Distance} = \sqrt{13}\)

Therefore, the distance of the point (2, 3) from the origin is​ \(\sqrt{13}\)  units.

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