Question
Download Solution PDFThe general solution of cot θ + tan θ = 2 is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
Given cot θ + tan θ = 2
\(\rm {1\over \tanθ} +\tan θ = 2\)
tan2 θ - 2 tan θ + 1 = 0
(tan θ - 1)2 = 0
tan θ = 1
θ = \({\pi\over4}, {5\pi\over4}, {9\pi\over4}...\) = \(\frac{{n\pi }}{2} + {( - 1)^n}\frac{\pi }{4}\), (n ∈ N)
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