The HCF and LCM of 2 positive numbers are 4 and 80 respectively. If one of the numbers is 4 more than the other, find the smaller number. 

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DSSSB Assistant Teacher (Nursery) Official Paper (Held On: 19 Nov, 2019 Shift 3)
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  1. 16
  2. 32
  3. 12
  4. 20

Answer (Detailed Solution Below)

Option 1 : 16
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Detailed Solution

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Given:

HCF of two numbers = 4

LCM of two numbers = 80

One of the numbers is 4 more than the other

Formula used:

Product of two numbers = HCF × LCM

Calculation:

Let the smaller number be 4k

Then, the larger number = (4k + 4)

Now, the Product of two numbers = HCF × LCM

⇒ 4k(4k + 4) = 4 × 80

⇒ k(k + 1) = 20

k = 4 and it satisfy the equation.

Smaller number = 4k

⇒ 4(4) ⇒ 16

 The answer is 16.

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-> The DSSSB Assistant Teacher (Nursery) Notification was released for 1455 vacancies.

-> Candidates who are 12th-passed and have Diploma/Certificate in Nursery Teacher Education or B. Ed.(Nursery) are eligible for this post.

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-> Candidates must refer to the DSSSB Assistant Teacher Previous Year Papers to boost their preparation.

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