The maximum shear stress occurs at mid of the height of a:

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DDA JE Civil 01 Apr 2023 Shift 2 Official Paper
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  1. square section
  2. rectangular section
  3. triangular section
  4. circular section

Answer (Detailed Solution Below)

Option 3 : triangular section
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Detailed Solution

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Explanation

Maximum shear stress (\({\tau _{max}}\)) in the triangular cross-section is given by:

\({\tau _{\max }} = 1.5\) \({\tau _{avg}}\) at h/2 distance

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Where,

\({\tau _{avg}}\) = Average shear stress in the cross-section

Shear stress at the neutral axis of the cross-section is given by:

\({\tau _{N.A}} = 1.33\)  \({\tau _{avg}}\)

Important Points 

Section

τmaxavg

τNeutral axis / τavg 

Rectangular/square

3/2

3/2

Solid circular

4/3

4/3

Triangle

3/2

4/3

Diamond

9/8

1

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