The minute hand of a watch is 2 cm long. How far does its tip move in 45 minutes? (use π = 3.14) 

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AAI ATC Junior Executive 25 March 2021 Official Paper (Shift 3)
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  1. 3.14 cm
  2. 12.56 cm
  3. 6.28 cm
  4. 9.42 cm

Answer (Detailed Solution Below)

Option 4 : 9.42 cm
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Detailed Solution

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Given:

The minute hand of a watch is 2 cm long.

Formula Used: 

Arc length, l = r × θ 

l = arc length (in radian)

r = radius

θ = central angle in radian

1° = πc/180 

Calculation:

We know that,

Angle traced by the minute hand in 60 min = (2π)c

Angle traced by the minute hand in 45 min = \((\frac{2π}{60} × 45)^c = (\frac{3 π}{2})^c\) 

⇒ r = 2 cm and θ = \((\frac{3 π}{2})^c\)

⇒ l = r × θ 

⇒ l = \((2 × \frac{3 π}{2})\)

⇒ l = 3 π 

⇒ l = 3 × 3.14

⇒ l = 9.42

∴ It tip moves 9.42 in 45 minutes. 

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