The relative thickness of hydrodynamic and thermal boundary layer depends upon:

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  1. Mach Number
  2. Nusselt Number
  3. Reynolds Number
  4. Prandtl Number

Answer (Detailed Solution Below)

Option 4 : Prandtl Number
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Detailed Solution

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Explanation:

The relationship between the thermal boundary layer and the hydrodynamic boundary layer is given by Prandtl number 

Prandtl Number: It is defined as the ratio of momentum diffusivity to thermal diffusivity.

\(Pr = \frac{\nu }{\alpha } = \frac{{momentum\;diffusivity}}{{Thermal\;diffusivty}} = \frac{{\frac{\mu }{\rho }}}{{\frac{k}{{{c_p}\rho }}}} = \frac{{\mu {c_p}}}{k}\)

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The relationship between the two is given by the equation

\(\frac{{{\delta }}}{\delta_t } = P_r^{ \frac{1}{3}}\)

δ = the thickness of the hydrodynamic boundary layer; the region of flow where the velocity is less than 99% of the far-field velocity.

δT = the thickness of the thermal boundary layer; the region of flow where the local temperature nearly reaches the value (99%) of the bulk flow temperature

  • If Pr > 1 the momentum or hydrodynamic boundary layer will increase more compared to the thermal boundary layer. 
  • If Pr < 1 the thermal boundary layer will increase more compared to the momentum or hydrodynamic boundary layer.
  • If Pr = 1 The the thermal boundary layer and momentum or hydrodynamic boundary layer will increase at the same rate.

If the velocity and thermal boundary layers coincide then Pr = 1. 

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