Question
Download Solution PDFThe sum of two numbers is 288 and their HCF is 16. How many pairs of such numbers can be formed?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
The sum of two numbers is 288 and their HCF is 16
Calculations:
Let the ratio of number be x : y
So the numbers will be 16x & 16y (HCF is an integral part of a number)
According to the question
16x + 16y = 288
⇒ 16(x + y) = 288
⇒ x + y = 18
Pairs of x, y can be (1, 17) (5, 13) (7, 11)
So there can be only 3 pairs.
∴ The correct choice is option 1.
Last updated on Jul 21, 2025
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