Schmitt Trigger MCQ Quiz - Objective Question with Answer for Schmitt Trigger - Download Free PDF

Last updated on Mar 21, 2025

Latest Schmitt Trigger MCQ Objective Questions

Schmitt Trigger Question 1:

In the Schmitt trigger circuit shown, VCE(sat) = 0.1 V. The output logic low level is:  

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  1. 3.65 V
  2. 3.85 V
  3. 1.35 V
  4. 1.15 V

Answer (Detailed Solution Below)

Option 3 : 1.35 V

Schmitt Trigger Question 1 Detailed Solution

Explanation:

In the given Schmitt trigger circuit, we are required to find the output logic low level when VCE(sat) = 0.1 V.

A Schmitt trigger is a comparator circuit with hysteresis implemented by applying positive feedback to the non-inverting input of a comparator or differential amplifier. Schmitt triggers are used to convert a noisy analog input signal into a clean digital output signal.

The output of a Schmitt trigger circuit switches between high and low voltage levels, depending on the input voltage and the threshold voltages set by the circuit. The output logic low level is the voltage level of the output when the circuit is in the low state, which typically occurs when the input voltage is below the lower threshold voltage.

In a Schmitt trigger circuit, the output stage is usually an open-collector or open-drain configuration. When the output is low, the transistor in the output stage is saturated, and the output voltage is approximately equal to the saturation voltage of the transistor, VCE(sat).

Given that VCE(sat) = 0.1 V, the output logic low level can be determined as follows:

Step-by-Step Solution:

  1. Identify the saturation voltage of the transistor (VCE(sat)). In this case, VCE(sat) is given as 0.1 V.
  2. In the low state, the output voltage is approximately equal to VCE(sat).
  3. Therefore, the output logic low level is 0.1 V.

However, the given options are:

  • Option 1: 3.65 V
  • Option 2: 3.85 V
  • Option 3: 1.35 V
  • Option 4: 1.15 V

Since the output logic low level is typically very close to VCE(sat) (0.1 V), let's consider the given options:

  • Option 1: 3.65 V
  • Option 2: 3.85 V
  • Option 3: 1.35 V
  • Option 4: 1.15 V

Among these options, the one that aligns closest to the expected output logic low level is Option 3: 1.35 V. This value may represent the logic low level due to other factors in the circuit that might influence the saturation voltage slightly, but still, it is the closest to the given VCE(sat).

Correct Option Analysis:

The correct option is:

Option 3: 1.35 V

This option is closest to the expected output logic low level given the saturation voltage of the transistor in the Schmitt trigger circuit. The value of 1.35 V may be due to additional voltage drops or other circuit elements, but it is the best match among the provided options.

Additional Information

To further understand the analysis, let’s evaluate the other options:

Option 1: 3.65 V

This option is much higher than the expected output logic low level. A typical logic low level in a Schmitt trigger circuit should be close to the saturation voltage of the transistor, which is much lower than 3.65 V.

Option 2: 3.85 V

Similar to Option 1, this value is also too high to be considered as the output logic low level. The saturation voltage of the transistor in the output stage would not typically result in such a high voltage for the logic low state.

Option 4: 1.15 V

While this option is closer to the expected output logic low level than Options 1 and 2, it is still higher than the given VCE(sat) of 0.1 V. However, it is relatively close and could be a result of other circuit elements affecting the voltage slightly.

Conclusion:

Understanding the behavior of the Schmitt trigger circuit and the impact of the transistor's saturation voltage is essential for correctly identifying the output logic levels. The output logic low level is determined by the saturation voltage of the transistor, which is given as 0.1 V in this case. Among the provided options, Option 3: 1.35 V is the closest match, accounting for potential minor variations in the circuit. This analysis highlights the importance of considering all factors in the circuit when determining the output logic levels.

Schmitt Trigger Question 2:

Which of the following circuits may be used for converting a sine wave into a square wave?

  1. Schmitt Trigger
  2. Bistable Multivibrator
  3. Astable Multivibrator
  4. Monostable Multivibrator

Answer (Detailed Solution Below)

Option 1 : Schmitt Trigger

Schmitt Trigger Question 2 Detailed Solution

Schmitt Trigger:

  • It is a comparator circuit with positive feedback.
  • It is a Bi-stable circuit, having two stable states (+Vsat and -Vsat).
  • In this, input sine-wave is converted to a square wave
  • The output voltage changes its states whenever the input voltage exceeds certain voltage levels (i.e. VUT & VLT)

F4 S.B Madhu 13.03.20 D 6

F4 S.B Madhu 13.03.20 D 7

Condition

Differential input voltage

Output voltage

If Vin < VUT

Vd is +ve

Vout = +Vsat

If Vin > VUT

Vd is -ve

Vout = -Vsat

If Vin > VLT

Vd is -ve

Vout = -Vsat

If Vin < VLT

Vd is +ve

Vout = +Vsat

 

∴ The input sine-wave converted into a square wave

Schmitt Trigger Question 3:

Pulses of definite width can be obtained from irregular shaped pulses 

  1. when it is given as input to a monostable multivibrator 
  2. when it is given as triggering signal to a bistable multivibrator 
  3. when it is used as input to a Schmitt trigger 
  4. when it is used as input to a pulse transformer 

Answer (Detailed Solution Below)

Option 3 : when it is used as input to a Schmitt trigger 

Schmitt Trigger Question 3 Detailed Solution

The correct option is 3

Concept:

  • A Schmitt trigger is basically an inverting comparator circuit with positive feedback. 
  • The function of the Schmitt trigger is to convert any regular or irregular-shaped input waveform into a square wave output voltage or pulse.
  • Thus, it can shape a wave and also called as a squaring circuit and can be used as a square wave generator.
  • Schmitt trigger is a comparator circuit with hysteresis implemented by applying positive feedback to the non-inverting input of a comparator or differential amplifier.
  • It is an active circuit that converts an analog input signal to a digital output signal.
  • The circuit is named a "trigger" because the output retains its value until the input changes sufficiently to trigger a change.
  • In the non-inverting configuration, when the input is higher than a chosen threshold, then output is high.
  • When the input is below a different (lower) chosen threshold, then output is low, and when the input is between the two levels, then output retains its value.

Schmitt Trigger Question 4:

A Schmitt trigger converts slowly varying wave form into

  1. Sawtooth wave
  2. Triangular wave
  3. Sine wave
  4. Square wave

Answer (Detailed Solution Below)

Option 4 : Square wave

Schmitt Trigger Question 4 Detailed Solution

Schmitt trigger:

F2 Savita Engineering  21-7-22 D5

Schmitt trigger is a positive feedback comparator circuit that converts the sinusoidal input into a square wave.

The output of a Schmitt trigger circuit is always +VCC or -VCC

When VNI > VI , the output is +VCC

When VNI < VI , the output is -VCC

Working of Schmitt trigger:

Case 1: When Vref > Vin 

Vo = +VCC

\(V_{ref} = V_{UTP}=V_{cc}({R_2 \over R_1+R_2})\)

Case 2: When Vref < Vin 

Vo = -VCC

\(V_{ref} =V_{LTP}= -V_{cc}({R_2 \over R_1+R_2})\)

F2 Savita Engineering 21-7-22 D4

Schmitt Trigger Question 5:

Directions: The question consists of two statements, one labeled as ‘Statement (I)’ and the other labeled as ‘Statement (II)’. You are to examine these two statements carefully and select the answers to these items using the codes given below:

Statement (I): The function of the Schmitt trigger is to convert any regular or irregular shaped input waveform into a square wave output voltage or pulse.

Statement (II): Schmitt trigger is basically a bistable multivibrator.

  1. Both Statement (I) and Statement (II) are individually true and Statement (II) is the correct explanation of Statement (I).
  2. Both Statement (I) and Statement (II) are individually true, but Statement (II) is not the correct explanation of Statement (I).
  3. Statement (I) is true, but Statement (II) is false.
  4. Statement (I) is false, but Statement (II) is true.

Answer (Detailed Solution Below)

Option 2 : Both Statement (I) and Statement (II) are individually true, but Statement (II) is not the correct explanation of Statement (I).

Schmitt Trigger Question 5 Detailed Solution

Schmitt Trigger:

  • Schmitt trigger is basically a comparator circuit with positive feedback and hence it is also called a regenerative comparator.
  • When Op-Amp is positively saturated, a positive voltage is a feedback to the non-inverting input and this positive voltage holds the output in the HIGH (+Vsat) stage.
  • When the output voltage is negatively saturated, a negative voltage is a feedback to the non-inverting input, holding the output in(-Vsat) LOW state.
  • So, it is basically a bistable multivibrator.
  • The function of the Schmitt trigger is to convert any regular or irregular-shaped input waveform into a square wave output voltage or pulse.
  • If we have provided sinusoidal as input to the Schmitt trigger then it gives a square wave at the output side.

F4 S.B Madhu 13.03.20 D 6

F4 S.B Madhu 13.03.20 D 7

Additional Information

  • Schmitt trigger is a comparator circuit with hysteresis implemented by applying positive feedback to the non-inverting input of a comparator or differential amplifier.
  • It is an active circuit which converts an analog input signal to a digital output signal.
  • The circuit is named a "trigger" because the output retains its value until the input changes sufficiently to trigger a change.
  • In the non-inverting configuration, when the input is higher than a chosen threshold, then output is high.
  • When the input is below a different (lower) chosen threshold, then output is low, and when the input is between the two levels, then output retains its value.
  • This dual threshold action is called hysteresis and implies that the schmitt trigger possesses memory and can act as a bistable multivibrator (latch or flip-flop).
  • Schmitt trigger devices are typically used in signal conditioning applications to remove noise from signals used in digital circuits, particularly mechanical contact bounce in switches.
  • They are also used in closed loop negative feedback configurations to implement relaxation oscillators, used in function generators and switching power supplies.
  • Note that, the Schmitt trigger can also be used with a current source to produce a sawtooth or triangle wave.

Top Schmitt Trigger MCQ Objective Questions

Schmitt trigger exhibits ________ effect.

  1. Hysteresis
  2. Hall
  3. Accelerator
  4. Illumination

Answer (Detailed Solution Below)

Option 1 : Hysteresis

Schmitt Trigger Question 6 Detailed Solution

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Schmitt trigger:

  • Schmitt trigger is a comparator circuit with a hysteresis effect implemented by applying positive feedback to the non-inverting input of a comparator or differential amplifier.
  • It is an active circuit that converts an analog input signal to a digital output signal.
  • When the input is below a different (lower) chosen threshold the output is low, and when the input is between the two levels the output retains its value. This dual threshold action is called hysteresis.
  • The Schmitt trigger possesses memory and can act as a bistable multivibrator.
  • It is called the transfer characteristics of the Schmitt trigger.

F1 Koda.R 13-02-21 Savita D2

Hall Effect: When a current-carrying conductor is placed perpendicular to the magnetic field, then an Electric field is produced, which is perpendicular to both.

F1 Koda.R 13-02-21 Savita D3

In a Schmitt Trigger UTP = 12V, LTP = 8V, the hysteresis VH is

  1. 12 V
  2. 8 V
  3. 4 V
  4. 20 V

Answer (Detailed Solution Below)

Option 3 : 4 V

Schmitt Trigger Question 7 Detailed Solution

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Concept:

The input voltage Vi changes the state of output therefore it exceeds its voltage level above a certain value called upper and lower threshold voltages.

The upper threshold point:

\({V_{UTP}} = {V_R} \times \frac{{{R_1}}}{{{R_1} + {R_2}}} + {V_0}\frac{{{R_2}}}{{{R_1} + {R_2}}}\)

Lower threshold point:

\({V_{LTP}} = {V_R}\frac{{{R_1}}}{{{R_1} + {R_2}}} - {V_0}\;\frac{{{R_2}}}{{{R_1} + {R_2}}}\)

Now, VH = VUTP - VLTP (hysteresis voltage)

Calculation:

Hysteresis Voltage

VH = VUTP - VLTP = 12 - 8 = 4 V

Additional Information

  • Schmitt trigger is a comparator circuit with a hysteresis effect implemented by applying positive feedback to the non-inverting input of a comparator or differential amplifier.
  • It is an active circuit that converts an analog input signal to a digital output signal.
  • When the input is below a different (lower) chosen threshold the output is low, and when the input is between the two levels the output retains its value. This dual threshold action is called hysteresis.
  • The Schmitt trigger possesses memory and can act as a bistable multivibrator.
  • It is called the transfer characteristics of the Schmitt trigger.

F1 Koda.R 13-02-21 Savita D2

A Schmitt trigger converts slowly varying wave form into

  1. Sawtooth wave
  2. Triangular wave
  3. Sine wave
  4. Square wave

Answer (Detailed Solution Below)

Option 4 : Square wave

Schmitt Trigger Question 8 Detailed Solution

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Schmitt trigger:

F2 Savita Engineering  21-7-22 D5

Schmitt trigger is a positive feedback comparator circuit that converts the sinusoidal input into a square wave.

The output of a Schmitt trigger circuit is always +VCC or -VCC

When VNI > VI , the output is +VCC

When VNI < VI , the output is -VCC

Working of Schmitt trigger:

Case 1: When Vref > Vin 

Vo = +VCC

\(V_{ref} = V_{UTP}=V_{cc}({R_2 \over R_1+R_2})\)

Case 2: When Vref < Vin 

Vo = -VCC

\(V_{ref} =V_{LTP}= -V_{cc}({R_2 \over R_1+R_2})\)

F2 Savita Engineering 21-7-22 D4

The Schmitt trigger circuit shown in the figure below uses a Zener diode with Vd = 0.7 V and breakdown voltage as 6 V. If the threshold voltage V1 is zero and hysteresis voltage VH = 0.2 V, then what is \(\frac{{{R_1}}}{{{R_2}}}\) and VR?

F1 U.B 19.6.20 Pallavi D 1

  1. R1/R2 = 6 and VR = 0.15 V
  2. R1/R2 = 67 and VR = -0.15 V
  3. R1/R2 = 66 and VR = -0.10 V
  4. R1/R2 = 66 and VR = -0.15 V

Answer (Detailed Solution Below)

Option 3 : R1/R2 = 66 and VR = -0.10 V

Schmitt Trigger Question 9 Detailed Solution

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Concept:

The input voltage Vi changes the state of output therefore it exceeds its voltage level above a certain value called upper and lower threshold voltages.

The upper threshold point:

\({V_{UTP}} = {V_R} \times \frac{{{R_1}}}{{{R_1} + {R_2}}} + {V_0}\frac{{{R_2}}}{{{R_1} + {R_2}}}\)

Lower threshold point:

\({V_{LTP}} = {V_R}\frac{{{R_1}}}{{{R_1} + {R_2}}} - {V_0}\;\frac{{{R_2}}}{{{R_1} + {R_2}}}\)

Now, VH = VUTP - VLTP (hysteresis voltage)

Calculation:

In Schmitt trigger, Zener diode voltage vd = 0.7 V

Threshold voltage V1 = 0

Hysteresis voltage VH = 0.2 V

\(\Rightarrow {V_H} = {V_R}\frac{{{R_1}}}{{{R_1} + {R_2}}} + {V_0}\frac{{{R_2}}}{{{R_1} + {R_2}}} - \left( {{V_R}\frac{{{R_1}}}{{{R_1} + {R_2}}} - {V_0}\frac{{{R_2}}}{{{R_1} + {R_2}}}} \right)\)

\(\Rightarrow {V_H} = 2\;{V_0}\frac{{{R_2}}}{{{R_1} + {R_2}}}\)

Now, V0 = VZ + VD = 0.7 + 6 = 6.7 V

\( \Rightarrow 0.2 = 2 \times 6.7 \times \frac{1}{{1 + \frac{{{R_1}}}{{{R_2}}}}}\)

\( \Rightarrow 1 + \frac{{{R_1}}}{{{R_2}}} = 67\)

\(\Rightarrow \frac{{{R_1}}}{{{R_2}}} = 66\)

Now, (threshold) \({V_1} = {V_R} \times \frac{{{R_1}}}{{{R_1} + {R_2}}} + {V_0} \times \frac{{{R_2}}}{{{R_1} + {R_2}}}\)

\(\Rightarrow 0 = {V_R}\frac{1}{{1 + \frac{{{R_2}}}{{{R_1}}}}} + {V_0}\frac{1}{{1 + \frac{{{R_1}}}{{{R_2}}}}}\)

\( \Rightarrow {V_2} \times \frac{1}{{1 + \frac{1}{{66}}}} = - 6.7 \times \frac{1}{{1 + 66}}\)

\(\Rightarrow {V_R} = \; - 6.7 \times \frac{1}{6} = - 0.10\;V\)

When a sinusoidal voltage wave drives a Schmitt Trigger, the output is a:

  1. Triangular wave
  2. Rectified sine wave
  3. Rectangular wave
  4. Trapezoidal wave

Answer (Detailed Solution Below)

Option 3 : Rectangular wave

Schmitt Trigger Question 10 Detailed Solution

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Schmitt Trigger:

  • It is a comparator circuit with positive feedback.
  • It is a Bi-stable circuit, having two stable states (+Vsat and -Vsat).
  • In this, the input sine-wave is converted to an ​asymmetrical square wave or rectangular wave. 
  • The output voltage changes its states whenever the input voltage exceeds certain voltage levels (i.e. VUT & VLT)

 

F4 S.B Madhu 13.03.20 D 6

F4 S.B Madhu 13.03.20 D 7

The output waveform for a sinusoidal input is a rectangular wave.

A CMOS Schmitt-trigger inverter has a low output level of 0 V and a high output level of 5 V. It has input thresholds of 1.6 V and 2.4 V. The input capacitance and output resistance of the Schmitt-trigger are negligible. The frequency of the oscillator shown is ______ Hz. (Round off to 2 decimal places.)

F1 Shraddha Koda 20.02.2021 D17

Answer (Detailed Solution Below) 3150 - 3170

Schmitt Trigger Question 11 Detailed Solution

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Given:

High output voltage level = 5 V

Lower threshold voltage = 1.6 V

Upper threshold voltage = 2.4 V

Resistance (R) = 10 kΩ 

Capacitance (C) = 47 nF

t1 = Capacitor charging time

t2 = Capacitor discharging time

Capacitor charging diagram is given as:

F1 Shraddha Koda 01.03.2021 D2

In case of charging voltage across capacitor Vc(t) is given as:

Vc(t) = Vcf + (Vci - Vcf) e-t/RC

Where Vcf = Final value of voltage across capacitor (= 5 V)

Vci = Initial value of voltage across capacitor (= 1.6 V)

In case of discharging voltage across capacitor Vc(t) is given as:

Vc(t) = Vci e-t/RC

RC = 10 × 103 × 47 × 10-9 = 470 × 10-6

At the end of charging time (t1), voltage across capacitor is = 2.4 V

Vc(t) = 2.4 = 5 + (1.6 - 5) e-t1/(470 × 10-6)

t1 = 126.1 × 10-6 s

At the end of discharging time (t2), voltage across capacitor is = 1.6 V

Vc(t) = 1.6 = 2.4 e-t2/(470 × 10-6)

t2 = 190.57 × 10-6 s

T = t1 + t2 = 126.1 × 10-6 + 190.57 × 10-6 = 316.67 × 10-6 s

Frequency = 1/T = 1/(316.67 × 10-6) = 3157.87 Hz

Which of the following circuits is used for converting a sine wave into a square wave?

  1. Monostable multivibrator
  2. Bistable multivibrator
  3. Schmitt trigger circuit
  4. Darlington complementary pair

Answer (Detailed Solution Below)

Option 3 : Schmitt trigger circuit

Schmitt Trigger Question 12 Detailed Solution

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Schmitt Trigger:

  • It is a comparator circuit with positive feedback.
  • It is a Bi-stable circuit, having two stable states (+Vsat and -Vsat).
  • In this, input sine-wave is converted to a square wave
  • The output voltage changes its states whenever the input voltage exceeds certain voltage levels (i.e. VUT & VLT)

F4 S.B Madhu 13.03.20 D 6

F4 S.B Madhu 13.03.20 D 7

\({v_0} = {A_{0L}} \cdot {V_d} = {A_{OL}}\left( {{v_f} - {v_{in}}} \right)\)

Condition

Differential input voltage

Output voltage

If Vin < VUT

Vd is +ve

Vout = +Vsat

If Vin > VUT

Vd is -ve

Vout = -Vsat

If Vin > VLT

Vd is -ve

Vout = -Vsat

If Vin < VLT

Vd is +ve

Vout = +Vsat

 

∴ The input sine-wave converted into a square wave

For the circuit with an ideal OPAMP shown in the figure. VREF is fixed.

F1 Shraddha Shubham 22.02.2021 D 12

If VOUT = 1 for VIN = 0.1 volt and VOUT = 6 volt for VIN = 1 volt, where VOUT is measured across RL connected at the output of this OPAMP, the value of RF / RIN is

  1. 3.285
  2. 5.555
  3. 2.860
  4. 3.825

Answer (Detailed Solution Below)

Option 2 : 5.555

Schmitt Trigger Question 13 Detailed Solution

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Concept:

When VIN is active and VREF = 0, the circuit is drawn as:

F1 Shraddha Shubham 22.02.2021 D 10

\({V_{OUT1}} = - \frac{{{R_F}}}{{{R_{IN}}}}{V_{IN}}\)  

When VIN = 0 and VREF is active, the circuit is drawn as:

F1 Shraddha Shubham 22.02.2021 D 11

\({V_{OU{T_2}}} = \left( {\frac{{{V_{REF}} \times {R_2}}}{{{R_1} + {R_2}}}} \right)\left( {1 + \frac{{{R_F}}}{{{R_{IN}}}}} \right)\)

Total Vout = Vout1 + Vout2

\({V_{out}} = \left( {\frac{{{V_{REF}} \times {R_2}}}{{{R_1} + {R_2}}}} \right)\left( {1 + \frac{{{R_F}}}{{{R_{IN}}}}} \right) - \frac{{{R_E}}}{{{R_{IN}}}}\;{V_{IN}}\)

F1 Shraddha Shubham 22.02.2021 D 12

Given VREF is fixed then V+ is fixed, i.e.

\({V^ + } = \frac{{{V_{REF}} \times {R_2}}}{{{R_1} + {R_2}}}\)

\({V_{OUT}} = \left( {1 + \frac{{{R_F}}}{{{R_{IN}}}}} \right)\left( {\frac{{{V_{REF}}\;{R_2}}}{{{R_1} + {R_2}}}} \right) - \frac{{{R_F}}}{{{R_{IN}}}}{V_{IN}}\)

For VIN = 0.1 V, we have VOUT = 1 V

\(1 = \left( {1 + \frac{{{R_F}}}{{{R_{IN}}}}} \right)\left( {\frac{{{V_{REF}}\;{R_2}}}{{{R_1} + {R_2}}}} \right) - \frac{{{R_F}}}{{{R_{IN}}}}\left( {0.1} \right)\)        ---(i)

For VIN = 10 V, we have VOUT = 6 V

\(6 = \left( {1 + \frac{{{R_F}}}{{{R_{IN}}}}} \right)\left( {\frac{{{V_{REF}}\;{R_2}}}{{{R_1} + {R_2}}}} \right) - \frac{{{R_F}}}{{{R_{IN}}}}\left( 1 \right)\)      ---(ii)

From (i)

\(\left( {1 + \frac{{{R_F}}}{{{R_{IN}}}}} \right)\left( {\frac{{{V_{REF}} \cdot {R_2}}}{{{R_1} + {R_2}}}} \right) = 1 + \frac{{{R_F}}}{{{R_{IN}}}}\left( {0.1} \right)\)

Putting above value in eq (ii)

\(6 = 1 + \frac{{{R_F}}}{{{R_{IN}}}}\left( {0.1} \right) - \frac{{{R_F}}}{{{R_{IN}}}}\left( 1 \right)\)

\(5 = \frac{{{R_F}}}{{{R_{IN}}}}\left( { - 0.9} \right)\)

\(\frac{{{R_F}}}{{{R_{IN}}}} = - \frac{5}{{0.9}} = - 5.55\)

Since only positive values are given in the options:

\(\frac{{{R_F}}}{{{R_{IN}}}} = 5.55\)

Which of the following circuits is used as a comparator?

  1. Astable multivibrator
  2. Bistable multivibrator
  3. Monostable multivibrator
  4. Schmitt trigger

Answer (Detailed Solution Below)

Option 4 : Schmitt trigger

Schmitt Trigger Question 14 Detailed Solution

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Schmitt trigger acts as a comparator when the input voltage is greater than UTP then the output will change from –Vsat to +Vsat.

Similarly, when the input voltage is less than LTP then the output will change from Vsat to -Vsat.

Which one of the following circuits is used fo converting a sine wave into a square wave?

  1. Astable multivibrator.
  2. Monostable multivibrator.  
  3. Bistable multivibrator.
  4. Schmitt trigger.

Answer (Detailed Solution Below)

Option 4 : Schmitt trigger.

Schmitt Trigger Question 15 Detailed Solution

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Schmitt Trigger:

  • It is a comparator circuit with positive feedback.
  • It is a Bi-stable circuit, having two stable states (+Vsat and -Vsat).
  • In this, input sine-wave is converted to a square wave
  • The output voltage changes its states whenever the input voltage exceeds certain voltage levels (i.e. VUT & VLT)

F4 S.B Madhu 13.03.20 D 6

F4 S.B Madhu 13.03.20 D 7

\({v_0} = {A_{0L}} \cdot {V_d} = {A_{OL}}\left( {{v_f} - {v_{in}}} \right)\)

Condition

Differential input voltage

Output voltage

If Vin < VUT

Vd is +ve

Vout = +Vsat

If Vin > VUT

Vd is -ve

Vout = -Vsat

If Vin > VLT

Vd is -ve

Vout = -Vsat

If Vin < VLT

Vd is +ve

Vout = +Vsat

 

∴ The input sine-wave converted into a square wave

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