Find the value of Req or (Rab ) in the following network.

F6 Madhuri Engineering 30.06.2022 D9

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NHPC JE Electrical 5 April 2022 (Shift 1) Official Paper
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  1. 12 Ω
  2. 4 Ω
  3. 20 Ω
  4. 24 Ω

Answer (Detailed Solution Below)

Option 1 : 12 Ω
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Detailed Solution

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CONCEPT:

  • Resistance: The obstruction offered to the flow of current is known as resistance. It is denoted by R.
  • When two or more resistances are connected one after another such that the same current flows through them then it is called resistances in series.
  • The equivalent resistance in series combination is will be
    Rser = R+ R+ R3
    F1 Jitendra Deepak 30.03.2020 D7
  • When the terminals of two or more resistances are connected at the same two points and the potential difference across them is equal then it is called resistances in parallel.F1 Jitendra Deepak 30.03.2020 D8
  • The net resistance/equivalent resistance(R) of resistances in parallel is given by:
    \(\frac{1}{R} = \frac{1}{{{R_1}}} + \frac{1}{{{R_2}}}\)
     

EXPLANATION:

Given that,

F6 Madhuri Engineering 30.06.2022 D9

Here, 10 Ω is connected parallel with 40 Ω and 20 Ω is connected parallel with 5 Ω and both parallel connections are connected together.

Hence, equivalent resistance (R) will be given as,

R = (20 || 5) + (10 || 40) Ω

or, R = \(\frac{20\times 5}{20+5}+\frac{10\times 40}{10+40}=12\ Ω\)

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