Question
Download Solution PDFIf two resistances of 10 Ω each are connected in parallel, then the equivalent resistance is-
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Addition in Series \(R_{eq}\) = R1 + R2 + R3.
Addition in Parallel \(\frac{1}{{{R_{eq}}}} = \frac{1}{{{R_1}}} + \frac{1}{{{R_2}}} + \frac{1}{{{R_3}}}\).
Calculation:
Given that \(R_1\) , \(R_2\)= 10 \(\Omega\).
\(R_1\) and \(R_2\) are connected in parallel.
\(\frac{1}{{{R_{eq}}}} = \frac{1}{{{R_1}}} + \frac{1}{{{R_2}}}\)
\(\frac{1}{{{R_{eq}}}} = \frac{1}{{{10}}} + \frac{1}{{{10}}}\)
\(R_{eq}\) = 5 \(\Omega\).
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