एक AC परिपथ में R = 100 Ω, C = 2 μF और L = 80 mH, श्रेणीक्रम में जुड़े हुए हैं। परिपथ का गुणता कारक है:

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AIIMS BSc NURSING 2023 Memory-Based Paper
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  1. 2
  2. 0.5
  3. 20
  4. 400

Answer (Detailed Solution Below)

Option 1 : 2
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गणना:
LC परिपथ के गुणता कारक (Q) का सूत्र इस प्रकार दिया गया है:

Q = (1 / R) × √(L / C)

जहाँ:

  • R = प्रतिरोध = 100 Ω
  • L = प्रेरकत्व = 80 mH = 80 × 10-3 H
  • C = धारिता = 2 μF = 2 × 10-6 F

सूत्र में मान प्रतिस्थापित करने पर:

Q = (1 / 100) × √((80 × 10-3) / (2 × 10-6))

Q = (1 / 100) × √(40 × 103)

Q = (1 / 100) × 200

Q = 2

परिपथ का गुणता कारक 2 है।

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