Question
Download Solution PDFएकल फेज ट्रांसफॉर्मर के लिए, 75% भार पर दक्षता अधिकतम होती है, तब \(\rm \frac{iron \ loss \ at\ full \ load }{copper \ loss \ at\ full \ load}=?\)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसही उत्तर विकल्प 4): \(\frac{9}{16}\) है
संकल्पना:
ट्रांसफॉर्मर अधिकतम दक्षता तब देगा जब उसका कॉपर क्षय, आयरन क्षय के बराबर होगा। पूर्ण भार के कुछ अंश x पर दक्षता अधिकतम होती है।
\(x = \sqrt {\frac{{{W_i}}}{{{W_{cu}}}}}\)
जहाँ
x दक्षता है
Wi = आयरन क्षय (वाट में)
Wcu = कॉपर क्षय (वाट में)
गणना:
दिया गया है
x = 0.75
\(W_i \over W_c\) = (0.75)2
= ( \(75 \over 100\))2
= ( \(3 \over 4\) )2
= \(9 \over 16\)
Last updated on May 9, 2025
-> PGCIL Diploma Trainee result 2025 will be released in the third week of May.
-> The PGCIL Diploma Trainee Answer key 2025 has been released on 12th April. Candidates can raise objection from 12 April to 14 April 2025.
-> The PGCIL DT Exam was conducted on 11 April 2025.
-> Candidates had applied online from 21st October 2024 to 19th November 2024.
-> A total of 666 vacancies have been released.
-> Candidates between 18 -27 years of age, with a diploma in the concerned stream are eligible.
-> Attempt PGCIL Diploma Trainee Previous Year Papers for good preparation.