Question
Download Solution PDFयदि मेमोरी चिप का आकार 1024 × 4 है, तो 8 k मेमोरी को डिज़ाइन करने के लिए आवश्यक मेमोरी चिप्स की संख्या ___ है।
This question was previously asked in
ESE Electrical 2014 Paper 2: Official Paper
Answer (Detailed Solution Below)
Option 3 : 16
Free Tests
View all Free tests >
ST 1: UPSC ESE (IES) Civil - Building Materials
6.2 K Users
20 Questions
40 Marks
24 Mins
Detailed Solution
Download Solution PDFमेमोरी का आकार = 8 k = 8 × 210 × 8 बिट
प्रत्येक मेमोरी चिप का आकार = 1024 × 4 = 210 × 4
आवश्यक मेमोरी चिप्स की संख्या = मेमोरी का आकार/प्रत्येक मेमोरी चिप का आकार
\( = \frac{{8 \times {2^{10}} \times 8}}{{{2^{10}} \times 4}} = 16\)
Latest UPSC IES Updates
Last updated on May 28, 2025
-> UPSC ESE admit card 2025 for the prelims exam has been released.
-> The UPSC IES Prelims 2025 will be held on 8th June 2025.
-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.
-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.
India’s #1 Learning Platform
Start Complete Exam Preparation
Daily Live MasterClasses
Practice Question Bank
Mock Tests & Quizzes
Trusted by 7.2 Crore+ Students
Crack UPPSC AE Stage I with
India's Super Teachers