Question
Download Solution PDFIf the memory chip size is 1024 × 4, the number of memory chips required to design 8 k bytes of memory is
This question was previously asked in
ESE Electrical 2014 Paper 2: Official Paper
Answer (Detailed Solution Below)
Option 3 : 16
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ST 1: UPSC ESE (IES) Civil - Building Materials
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Detailed Solution
Download Solution PDFSize of memory = 8 k = 8 × 210 × 8 bits
Size of each memory chip = 1024 × 4 = 210 × 4
Number of memory chips required = Size of memory/Size of each memory chip
\( = \frac{{8 \times {2^{10}} \times 8}}{{{2^{10}} \times 4}} = 16\)
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