Question
Download Solution PDFचित्र में दिखाए गए स्टार-डेल्टा रूपांतरण में, यदि P = 150 Ω, Q = 180 Ω और R = 60 Ω, तो A = ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFस्टार से डेल्टा रूपांतरण
स्टार से जुड़े प्रतिरोधक का डेल्टा समतुल्य है:
\(R_A={R_PR_Q+R_QR_R+R_RR_P\over R_R}\)
\(R_B={R_PR_Q+R_QR_R+R_RR_P\over R_Q}\)
\(R_C={R_PR_Q+R_QR_R+R_RR_P\over R_P}\)
गणना
दिया गया है, P = 150 Ω, Q = 180 Ω और R = 60 Ω
\(R_A={150\times 180+180\times 60+60\times 150\over 60}\)
\(R_A=780\space {\Omega}\)
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