The ________ is equal to the product of the force applied and radius of the shaft.

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JKSSB JE CE 2021 Official Paper Shift 1 (Held on 29 Oct 2021)
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  1. moment
  2. resilience
  3. force
  4. torsion

Answer (Detailed Solution Below)

Option 4 : torsion
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Detailed Solution

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Explanation:

Torque

  • It is the turning moment of a wheel measured in N-m and is the power required to overcome the resistance to move.
  • Torque is a product of the force applied at a tangent and the radius of the shaft.

Additional Information

Moment of a force 

Varingon’s theorem states that if many coplanar forces are acting on a body, then the algebraic sum of moments of all the forces about a point in the plane of the forces is equal to the moment of their resultant about the same point.

F1 Krupalu Madhu 25.08.20 D5

  • The moment of the resultant force about point O is given as, 
  • Mo = (F1a) + (F2b) + (F3c) + M1 + M2
  • The algebraic sum of moments of the forces forming a couple about any point in their plane is equal to the moment of the couple.
  • The moment of a force about any point is the Product of force and the perpendicular distance between the point and line of action of the force.
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