The circuit shown below will:

F1 Shubham.B 19-01-21 Savita D10

This question was previously asked in
VSSC (ISRO) Technician B (Electronic Mechanic) Previous Year Paper (Held on 25 Sept 2016)
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  1. Pass higher frequencies
  2. Pass lower frequencies
  3. Block higher frequencies
  4. Block a range of frequencies

Answer (Detailed Solution Below)

Option 1 : Pass higher frequencies
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Detailed Solution

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Concept:

The inductive reactance is given by:

XL = jωL

ω = frequency applied

L = Inductance

Analysis:

For ω (Input frequency) = 0 rad/s:

The inductive reactance will be:

XL = j(0)L = 0 Ω (Short circuit)

The circuit is drawn as:

F2 Shubham Bhatt 3.3.21 Pallavi D13

The output voltage is therefore 0 V.

For ω (Input frequency) = rad/s:

The inductive reactance will be:

XL = j()L =  Ω (Open circuit)

The circuit is drawn as:

F2 Shubham Bhatt 3.3.21 Pallavi D14

The output voltage is therefore 10 V.

ConclusionThe circuit does not allow low frequencies to pass and only passes high frequencies. Option (1) is correct.

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