The Rankine's formula holds good for

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  1. short columns
  2. long columns
  3. both short and long columns
  4. weak columns

Answer (Detailed Solution Below)

Option 3 : both short and long columns
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Explanation:

For short or long columns Rankine’s Formula is used.

\(\frac{1}{P} = \frac{1}{{{P_C}}} + \frac{1}{{{P_E}}}\)

Where P is crippling load by Rankine formula; \({P_C}\;\) is crushing load; \({P_E}\;\) is crippling load by Euler’s formula.

For Short column\({P_E}\;\) is very large so \(\frac{1}{{{P_E}}}\)  will be very small and negligible as compared to \(\frac{1}{{{P_C}}}.\) so

\(\frac{1}{P} = \frac{1}{{{P_C}}} \to P = {P_C}\)

For Long column: \({P_E}\;\) is small so \(\frac{1}{{{P_E}}}\) will be large as compared to. Hence the value of  \(\frac{1}{{{P_C}}}\;\) can be neglected. So

\(\frac{1}{P} = \frac{1}{{{P_E}}} \to P = {P_E}\)

Hence the crippling load by Rankine’s formula for a long column is approximately equal to the crippling load by Euler’s formula.
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