Question
Download Solution PDFA 25 kW, 250 V, DC shunt generator has armature and field resistances of 0.06 Ω and 100 Ω, respectively. Find the armature current.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The circuit diagram of DC shunt generator is shown below:
The current across the field resistance is given by:
\(I_{sh}={250\over 100}=2.5A\)
The load current is given by:
\(25\times 10^3=250\times I\)
I = 100 A
The armature current is:
\(I_a=I_{sh}+I_L\)
\(I_a=2.5+100\)
Ia = 102.5 A
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