Question
Download Solution PDFA capacitor of capacitive reactance 5 Ω is connected across a 220V, 50Hz supply. Calculate the maximum current drawn by the capacitor.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept of Capacitive Reactance:
Capacitive reactance (XC) is given by:
XC = 1 / (2πfC)
Where,
- f = Frequency of the supply
- C = Capacitance of the capacitor
Given Data:
- Capacitive Reactance (XC) = 5 Ω
- Voltage (V) = 220 V
- Frequency (f) = 50 Hz
Calculation:
We know that the current (I) in a purely capacitive circuit is given by:
I = V / XC
Therefore,
I = 220 V / 5 Ω
⇒ I = 44 A (RMS)
IMAX = 44√2 A
Conclusion:
Hence, the maximum current drawn by the capacitor is 44√2 A.
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