A certain length of wire has its resistance measured as 20 Ω at 20°C and 40 Ω at 60°C. Calculate the temperature coefficient.

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  1. \(\left(\frac{1}{30}\right)\,\)/°C
  2. \(\left(\frac{1}{60}\right)\,\)/°C
  3. 30°C
  4. \(\left(\frac{1}{40}\right)\,\)/°C

Answer (Detailed Solution Below)

Option 4 : \(\left(\frac{1}{40}\right)\,\)/°C
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Detailed Solution

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Concept of Temperature Coefficient of Resistance:

The temperature coefficient of resistance (α) quantifies how the resistance of a material changes with temperature. The formula to calculate α is:

Rt = R0 (1 + α (T - T0))

Where,

  • Rt = Resistance at temperature T
  • R0 = Resistance at reference temperature T0
  • α = Temperature coefficient of resistance
  • T = Final temperature
  • T0 = Initial temperature

Given Data:

  • R0 = 20 Ω at T0 = 20°C
  • Rt = 40 Ω at T = 60°C

Calculation:

Rearranging the formula to solve for α:

Rt = R0 (1 + α (T - T0))

40 = 20 (1 + α (60 - 20))

40 = 20 (1 + 40α)

Dividing both sides by 20, we get:

2 = 1 + 40α

Subtracting 1 from both sides, we get:

1 = 40α

Dividing both sides by 40, we get:

α = 1 / 40

⇒ α = 0.025 per °C

Conclusion:

Hence, the temperature coefficient of resistance is 0.025 per °C.

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